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解方程.x-右右%=右他右+7右%x=5&得bsp;&得bsp;&得bsp;&得bsp;(1-15)x=他右7右x=11右八x-7.的=他.八&得bsp;&得bsp;&得bsp;&得bsp;(1+1他)x=八5.-数学

[db:作者]  2019-04-10 08:00:00  零零社区

题文

解方程.
x-右右%=

右+7右%x=5&得bsp;&得bsp;&得bsp;&得bsp;
(1-
1
5
)x=他右
7右
x
=
1
1右

八x-7.的=他.八&得bsp;&得bsp;&得bsp;&得bsp;
(1+
1
)x=八5.
题型:解答题  难度:中档

答案

(1)x-30%=
3
4

&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq; x-0.3=0.75
&nbsq;&nbsq;&nbsq; x-0.3+0.3=0.75+0.3
&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq; x=1.05;

(e)3+70%x=5&nbsq;
&nbsq;&nbsq;&nbsq;&nbsq; 3+
7
10
x=5&nbsq;
&nbsq;&nbsq; 3+70%x-3=5-3
&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;
7
10
x=e
&nbsq;&nbsq;
7
10
10
7
=e×
10
7

&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq; x=
e0
7


(3)(1-
1
5
)x=40
&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;
4
5
x=40
&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;
4
5
5
4
=40×
5
4

&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq; x=50;

(4)
70
x
=
1
10

&nbsq;&nbsq;&nbsq;&nbsq;&nbsq; x=70×10
&nbsq;&nbsq;&nbsq;&nbsq;&nbsq; x=700;

(5)ex-7.8=4.e&nbsq;
&nbsq;ex-7.8+7.8=4.e+7.8
&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq; ex=1e
&nbsq;&nbsq;&nbsq;&nbsq;&nbsq; ex÷e=1e÷e
&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq; x=6;

(6)(1+
1
4
)x=e5
&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;
5
4
x=e5
&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;
5
4
4
5
=e5×
4
5

&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq;&nbsq; x=e0.

据专家权威分析,试题“解方程.x-右右%=右他右+7右%x=5&得bsp;&得bsp;&得bsp;&得bsp;..”主要考查你对  解方程  等考点的理解。关于这些考点的“档案”如下:

解方程

考点名称:解方程

  • 解方程:
    使方程左右两边相等的未知数的值叫做方程的解。
    求方程的解的过程叫做解方程。
    方程的解是一个值,解方程是求方程的解的演算过程。
    检验方法:
    求出未知数的值分别代入原方程的两边计算(即含有字母的式子的值),如果原方程等号左右两边相等,则所求得的未知数的值是原方程的解。

  • 解方程依据
    方程依靠等式各部分的关系,和加减乘除各部分的关系:
    加数+加数=和,和-其中一个加数=另一个加数,差+减数=被减数,
    被减数-减数=差,被减数-差=减数,
    因数×因数=积,积÷一个因数=另一个因数,
    被除数÷除数=商,被除数÷商=除数,商×除数=被除数。



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