(1)小球落到斜面上时的水平速度V
0、竖直速度V
y和实际速度V
t的矢量三角形如右图所示。
![](http://www.00-edu.com/d/file/2022-09-19/52b12eb6584c17742a0bc4938464b1e5.jpg)
由图可得:V
y = V
0tan53
0 =" 15×4/3" = 20(m/s),……(2分)
再由V
y = gt得:t = V
y/g =" 20/10" = 2(s)。…………(2分)
(2)因为X = V
0t =" 15×2" = 30(m),……………………………(2分)
Y =" g" t
2/2 = 10×2
2/2 = 20(m),…………………………………………(2分)
所以 h =" Y" + X·tan37
0 =" 20" + 30×3/4 = 42.5(m)。……………………(2分)