ÌâÎÄ

ijѧУҪӡˢһÅúÐû´«²ÄÁÏ£¬¼×Ó¡Îñ¹«Ë¾Ìá³öÊÕÖÆ°æ·Ñ900Ôª£¬ÁíÍâÿ·Ý²ÄÁÏÊÕÓ¡Ë¢·Ñ0.5Ôª£»ÒÒÓ¡Îñ¹«Ë¾Ìá³ö²»ÊÕÖÆ°æ·Ñ£¬Ã¿·Ý²ÄÁÏÊÕÓ¡Ë¢·Ñ0.8Ôª¡£ £¨1£©·Ö±ðд³öÁ½¼ÒÓ¡Îñ¹«Ë¾µÄÊÕ·Ñy£¨Ôª£©ÓëÓ¡Ë¢²ÄÁϵķÝÊýx£¨·Ý£©Ö®¼äµÄº¯Êý¹Øϵʽ£» £¨2£©ÈôѧУԤ¼ÆÒªÓ¡Ë¢5000·ÝÒÔÄÚµÄÐû´«²ÄÁÏ£¬ÇëÎÊѧУӦѡÔñÄÄÒ»¼ÒÓ¡Îñ¹«Ë¾¸üºÏË㣿

ÌâÐÍ£º½â´ðÌâ  ÄѶȣºÆ«ÄÑ

´ð°¸

½â£º£¨1£©¼×Ó¡Îñ¹«Ë¾µÄÊÕ·Ñy¼×=900+0.5x£» ÒÒÓ¡Îñ¹«Ë¾µÄÊÕ·ÑyÒÒ=0.8x£» £¨2£©µ±y¼×=yÒÒʱ£¬¼´900+0.5x=0.8x£¬ ½âµÃx=3000ʱ£¬Õâ˵Ã÷Ó¡Ë¢3000·ÝµÄÐû´«²ÄÁÏʱ£¬Á½¼ÒÓ¡Îñ¹«Ë¾Ò»Ñù±ãÒË£» µ±x>3000ʱ£¬ÓÐy¼×<yÒÒ£¬Õâ˵Ã÷Ó¡Ë¢³¬¹ý3000·ÝµÄÐû´«²ÄÁÏʱ£¬¼×Ó¡Îñ¹«Ë¾µÄÊշѽϱãÒË£¬Ñ¡Ôñ¼×Ó¡Îñ¹«Ë¾£» µ±x£¼3000ʱ£¬ÓÐy¼×£¾yÒÒ£¬Õâ˵Ã÷Ó¡Ë¢µÍÓÚ3000·ÝµÄÐû´«²ÄÁÏʱ£¬ÒÒÓ¡Îñ¹«Ë¾µÄÊշѽϱãÒË£¬Ñ¡ÔñÒÒÓ¡Îñ¹«Ë¾¡£

¾Ýר¼ÒȨÍþ·ÖÎö£¬ÊÔÌ⡰ijѧУҪӡˢһÅúÐû´«²ÄÁÏ£¬¼×Ó¡Îñ¹«Ë¾Ìá³öÊÕÖÆ°æ·Ñ900Ôª£¬ÁíÍâÿ..¡±Ö÷Òª¿¼²éÄã¶Ô  ÇóÒ»´Îº¯ÊýµÄ½âÎöʽ¼°Ò»´Îº¯ÊýµÄÓ¦Ó࠵ȿ¼µãµÄÀí½â¡£¹ØÓÚÕâЩ¿¼µãµÄ¡°µµ°¸¡±ÈçÏ£º

ÇóÒ»´Îº¯ÊýµÄ½âÎöʽ¼°Ò»´Îº¯ÊýµÄÓ¦ÓÃ

¿¼µãÃû³Æ£ºÇóÒ»´Îº¯ÊýµÄ½âÎöʽ¼°Ò»´Îº¯ÊýµÄÓ¦ÓÃ

• ´ý¶¨ÏµÊý·¨ÇóÒ»´Îº¯ÊýµÄ½âÎöʽ£º
  ÏÈÉè³öº¯Êý½âÎöʽ£¬ÔÙ¸ù¾ÝÌõ¼þÈ·¶¨½âÎöʽÖеÄδ֪ϵÊý£¬´Ó¶øµÃµ½º¯ÊýµÄ½âÎöʽµÄ·½·¨¡£
  
  Ò»´Îº¯ÊýµÄÓ¦Óãº
  Ó¦ÓÃÒ»´Îº¯Êý½âÓ¦ÓÃÌ⣬һ°ãÊÇÏÈд³öº¯Êý½âÎöʽ£¬ÔÚÒÀÕÕÌâÒ⣬Éè·¨Çó½â¡£
  £¨1£©ÓÐͼÏñµÄ£¬×¢Òâ×ø±êÖá±íʾµÄʵ¼ÊÒâÒå¼°µ¥Î»£»
  £¨2£©×¢Òâ×Ô±äÁ¿µÄÈ¡Öµ·¶Î§¡£

• Óôý¶¨ÏµÊý·¨ÇóÒ»´Îº¯Êý½âÎöʽµÄËĸö²½Ö裺
  µÚÒ»²½£¨É裩£ºÉè³öº¯ÊýµÄÒ»°ãÐÎʽ¡££¨³ÆÒ»´Îº¯Êýͨʽ£©
  µÚ¶þ²½£¨´ú£©£º´úÈë½âÎöʽµÃ³ö·½³Ì»ò·½³Ì×é¡£
  µÚÈý²½£¨Ç󣩣ºÍ¨¹ýÁз½³Ì»ò·½³Ì×éÇó³ö´ý¶¨ÏµÊýk£¬bµÄÖµ¡£
  µÚËIJ½£¨Ð´£©£ºÐ´³ö¸Ãº¯ÊýµÄ½âÎöʽ¡£
  
  Ò»´Îº¯ÊýµÄÓ¦ÓÃÉæ¼°ÎÊÌ⣺
  Ò»¡¢·Ö¶Îº¯ÊýÎÊÌâ
  ·Ö¶Îº¯ÊýÊÇÔÚ²»Í¬Çø¼äÓв»Í¬¶ÔÓ¦·½Ê½µÄº¯Êý£¬ÒªÌرð×¢Òâ×Ô±äÁ¿È¡Öµ·¶Î§µÄ»®·Ö£¬¼ÈÒª¿ÆѧºÏÀí£¬ÓÖÒª·û
  ºÏʵ¼Ê¡£

  ¶þ¡¢º¯ÊýµÄ¶à±äÁ¿ÎÊÌâ
  ½â¾öº¬Óжà±äÁ¿ÎÊÌâʱ£¬¿ÉÒÔ·ÖÎöÕâЩ±äÁ¿µÄ¹Øϵ£¬Ñ¡È¡ÆäÖÐÒ»¸ö±äÁ¿×÷Ϊ×Ô±äÁ¿£¬È»ºó¸ù¾ÝÎÊÌâµÄÌõ¼þÑ°
  Çó¿ÉÒÔ·´Ó³Êµ¼ÊÎÊÌâµÄº¯Êý

  Èý¡¢¸ÅÀ¨ÕûºÏ
  £¨1£©¼òµ¥µÄÒ»´Îº¯ÊýÎÊÌ⣺¢Ù½¨Á¢º¯ÊýÄ£Ð͵ķ½·¨£»¢Ú·Ö¶Îº¯Êý˼ÏëµÄÓ¦Óá£
  £¨2£©ÀíÇåÌâÒâÊDzÉÓ÷ֶκ¯Êý½â¾öÎÊÌâµÄ¹Ø¼ü¡£
  
  Éú»îÖеÄÓ¦Óãº
  1.µ±Ê±¼ätÒ»¶¨£¬¾àÀësÊÇËÙ¶ÈvµÄÒ»´Îº¯Êý¡£s=vt¡£
  2.Èç¹ûË®³Ø³éË®ËÙ¶ÈfÒ»¶¨£¬Ë®³ØÀïË®Á¿gÊdzéˮʱ¼ätµÄÒ»´Îº¯Êý¡£ÉèË®³ØÖÐÔ­ÓÐË®Á¿S¡£g=S-ft¡£
  3.µ±µ¯»ÉÔ­³¤¶Èb£¨Î´¹ÒÖØÎïʱµÄ³¤¶È£©Ò»¶¨Ê±£¬µ¯»É¹ÒÖØÎïºóµÄ³¤¶ÈyÊÇÖØÎïÖØÁ¿xµÄÒ»´Îº¯Êý£¬¼´y=kx+b£¨kΪÈÎÒâÕýÊý£©

• Ò»´Îº¯ÊýÓ¦Óó£Óù«Ê½£º
  1.Çóº¯ÊýͼÏñµÄkÖµ£º£¨y₁-y₂)/(x₁-x₂)
  2.ÇóÓëxÖáƽÐÐÏ߶εÄÖе㣺(x₁+x₂)/2
  3.ÇóÓëyÖáƽÐÐÏ߶εÄÖе㣺(y₁+y₂)/2
  4.ÇóÈÎÒâÏ߶εij¤£º¡Ì[(x₁-x₂)²+(y₁-y₂)² ]
  5.ÇóÁ½¸öÒ»´Îº¯ÊýʽͼÏñ½»µã×ø±ê£º½âÁ½º¯Êýʽ
  Á½¸öÒ»´Îº¯Êý y₁=k₁x+b₁; y₂=k₂x+b₂ Áîy₁=y₂ µÃk₁x+b₁=k₂x+b₂ ½«½âµÃµÄx=x0Öµ´ú»Øy₁=k₁x+b₁ ; y₂=k₂x+b₂ Á½Ê½ÈÎһʽ µÃµ½y=y₀ Ôò(x₀,y₀)¼´Îª y₁=k₁x+b₁ Óë y₂=k₂x+b₂ ½»µã×ø±ê
  6.ÇóÈÎÒâ2µãËùÁ¬Ï߶εÄÖеã×ø±ê£º[£¨x₁+x₂£©/2£¬£¨y₁+y₂£©/2]
  7.ÇóÈÎÒâ2µãµÄÁ¬ÏßµÄÒ»´Îº¯Êý½âÎöʽ£º£¨x-x₁£©/(x₁-x₂)=(y-y₁)/(y₁-y₂) (Èô·ÖĸΪ0£¬Ôò·Ö×ÓΪ0)
  £¨x,y£©Îª + £¬+£¨Õý£¬Õý£©Ê±¸ÃµãÔÚµÚÒ»ÏóÏÞ
  £¨x,y£©Îª - £¬+£¨¸º£¬Õý£©Ê±¸ÃµãÔÚµÚ¶þÏóÏÞ
  £¨x,y£©Îª - £¬-£¨¸º£¬¸º£©Ê±¸ÃµãÔÚµÚÈýÏóÏÞ
  £¨x,y£©Îª + £¬-£¨Õý£¬¸º£©Ê±¸ÃµãÔÚµÚËÄÏóÏÞ
  8.ÈôÁ½ÌõÖ±Ïßy₁=k₁x+b₁//y₂=k₂x+b₂£¬Ôòk₁=k₂£¬b₁¡Ùb₂
  9.ÈçÁ½ÌõÖ±Ïßy₁=k₁x+b₁¡Íy₂=k₂x+b₂£¬Ôòk₁¡Ák₂=-1
  10.
  y=k£¨x-n£©+b¾ÍÊÇÖ±ÏßÏòÓÒƽÒÆn¸öµ¥Î»
  y=k£¨x+n£©+b¾ÍÊÇÖ±ÏßÏò×óƽÒÆn¸öµ¥Î»
  y=kx+b+n¾ÍÊÇÏòÉÏƽÒÆn¸öµ¥Î»
  y=kx+b-n¾ÍÊÇÏòÏÂƽÒÆn¸öµ¥Î»
  ¿Ú¾ö£º×ó¼ÓÓÒ¼õÏà¶ÔÓÚx£¬ÉϼÓϼõÏà¶ÔÓÚb¡£
  11.Ö±Ïßy=kx+bÓëxÖáµÄ½»µã£º(-b/k£¬0) ÓëyÖáµÄ½»µã£º(0£¬b)