用递等式计算:(13+25)×15200-180÷15×6(3.8-1.8÷2)×0.3712÷9+19×512815×[(34-12)÷35].-数学
题文
用递等式计算: (
200-180÷15×6 (3.8-1.8÷2)×0.3
|
答案
①(
=
=5+6, =11; ②200-180÷15×6 =200-12×6, =200-72, =128; ③(3.8-1.8÷2)×0.3 =(3.8-0.9)×0.3, =2.9×0.3, =0.87; ④
=(
=1×
=
⑤
=
|
题文
用递等式计算: (
200-180÷15×6 (3.8-1.8÷2)×0.3
|
答案
①(
=
=5+6, =11; ②200-180÷15×6 =200-12×6, =200-72, =128; ③(3.8-1.8÷2)×0.3 =(3.8-0.9)×0.3, =2.9×0.3, =0.87; ④
=(
=1×
=
⑤
=
|