计算(1)(13-16+14)×(-24).(2)-24+12×[6+(-4)2](3)先化简,再求值:(3x2y-xy2)-3(x2y-2xy2),其中x=12,y=-13.(4)解方程:2x-16-3x-18=1(5)解方程组6x-3y=-35x-9y=4-数学
题文
计算(1)(
(2)-24+
(3)先化简,再求值:(3x2y-xy2)-3(x2y-2xy2),其中x=
(4)解方程:
(5)解方程组
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答案
(1)(
=
=-8+4-6, =-10; (2)原式=-24+
=-24+
=-16+11, =-5; (3)(3x2y-xy2)-3(x2y-2xy2), =3x2y-xy2-3x2y+6xy2, =5xy2, 当x=
原式=5×
=5×
=
(4)去分母得,4(2x-1)-3(3x-1)=24, 去括号得,8x-4-9x+3=24, 移项、合并同类项得,-x=25, 系数化为1得,x=-25; (5)
①×3-②得,13x=-13, 解得x=-1, 把x=-1代入①得,-6-3y=-3, 解得y=-1, 故原方程组的解为
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