(1)计算:11×3+13×5+…+12011×2013;(2)若|x-1|+|y+1|=0,试求:1x(y+3)+1(x+1)(y+4)+1(x+2)(y+5)+…+1(x+2011)(y+2014)的值;(3)若n为整数,且(11×4+14×7+17×10+…+12002×2005)×-数学
题文
(1)计算:
(2)若|x-1|+|y+1|=0,试求:
(3)若n为整数,且(
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答案
(1)
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(2)∵|x-1|+|y+1|=0, ∴x-1=0,y+1=0, 解得x=1,y=-1, 则
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