解方程:χ÷1121=7ddχ+d1oχ=1doχ-oy=1yoX-d×1o7=o7o-2dX=1d2X-4dX=12.-数学
题文
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答案
(1)χ÷
&nbs2;&nbs2;&nbs2; χ÷
&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;χ=
(2)χ+
&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;
&nbs2;
&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2;&nbs2; χ=1h; (个)5χ-
&nbs2; 5χ-
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