用递等式计算.(1)2184-[(44×19+44)÷5](2)450+(8.16+6.84)÷0.63(3)(45+14)÷75+56(4)[1-(112+18)×2]÷112(5)(4-7.5×415)÷29(6)712÷[(14+0.875)×89]-14.-数学
题文
用递等式计算.
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答案
(1)2184-[(44×19+44)÷5], =2184-[44×(19+1)÷5], =2184-[44×20÷5], =2184-[880÷5], =2184-176, =2008; (2)450+(8.16+6.84)÷0.63, =450+15÷0.63, =450+23
=473
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