用递等式计算:(1)2108+540÷18×24(2)(13+212)÷(2+323)(3)47×[0.75-(716-0.25)](4)[118+(0.65+720)÷17]×4.8.-数学
题文
用递等式计算: (1)2108+540÷18×24 (2)(
(3)
(4)[1
|
答案
(1)2108+540÷18×24, =2108+30×24, =2108+720, =2828; (2)(
=2
=
(3)
=
=
=
(4)[1
=[1
=[1
=8 |
题文
用递等式计算: (1)2108+540÷18×24 (2)(
(3)
(4)[1
|
答案
(1)2108+540÷18×24, =2108+30×24, =2108+720, =2828; (2)(
=2
=
(3)
=
=
=
(4)[1
=[1
=[1
=8 |