用递等式计算.(1)406+4480÷28(2)1757-189-157(3)38÷(78-14)×5.5(4)13÷54+23×45(5)5-(112+115)×30(6)[113-(2.5-123)]÷18.-数学

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89,
=14
1
9


(3)
3
8
÷(
7
8
-
1
4
)×5.5,
=
3
8
÷
5
8
×5.5,
=
3
5
×5.5,
=3.3;

(4)
1
3
÷
5
4
+
2
3
×
4
5

=
1
3
×
4
5
+
2
3
×
4
5

=(
1
3
+
2
3
)×
4
5

=1×
4
5

=
4
5


(5)5-(
1
12
+
1
15
)×30,
=5-(
1
12
×30+
1
15
×30),
=5-(2.5+2),
=5-4.5,
=0.5;
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