用递等式计算,能简算的要简算(417+125)×17×258.1÷〔(417-0.005×700)÷127+3〕1234÷1234123412359999×2222+3334×3333.-数学

题文

用递等式计算,能简算的要简算
4
17
+
1
25
)×17×25
8.1÷〔(4
1
7
-0.005×700)÷1
2
7
+3〕
1234÷1234
1234
1235
9999×2222+3334×3333.
题型:解答题  难度:中档

答案

(1)(
4
17
+
1
25
)×17×25,
=(
4
17
+
1
25
)×(17×25),
=(
4
17
×17×25)+(
1
25
×25×17),
=(4×25)+(1×17),
=100+17,
=117;

(2)8.1÷[(4
1
7
-0.005×700)÷1
2
7
+3],
=8.1÷[(4
1
7
-3.5)÷1
2
7
+3],
=8.1÷[
9
14
÷1
2
7
+3],
=8.1÷[
1
2
+3],
=8.1÷3
1
2

=
81
35


(3)1234÷1234
1234
1235

=1234÷
1234×1235+1234
1235

=1234÷
1234×(1235+1)
1235

=1234÷
1234×1236
1235

=1234×
1235
1234×1236

=
1235
1236


(4)9999×2222+3334×3333,
=3333×6666+3334×3333,
=3333×(6666+3334),
=3333×10000,
=33330000.

据专家权威分析,试题“用递等式计算,能简算的要简算(417+125)×17×258.1÷〔(417-0.005..”主要考查你对  分数的四则混合运算及应用  等考点的理解。关于这些考点的“档案”如下:

  • 最新内容
  • 相关内容
  • 网友推荐
  • 图文推荐